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These 5- and 6-mark questions come up again and again, and the mark scheme wants the same six points every time. Learn the chain once, then fill in the objects from the question.
The notes: the chain, how to mark up a question and every worked answer. Or just the questions, with the chain checklist at the top and the answers at the back.
“With reference to Newton’s laws of motion, explain…”
…followed by a scenario and a picture: a rocket, a balloon car, a passenger holding a pole, ice whizzing across water. Object A pushes on object B, and object A accelerates. That’s your cue for the Newton chain.
Ring three things in the question. They’re the only parts of your answer that change from question to question.
The thing the question asks about: the ice, the car, the passenger.
The gas, the air, the pole. A pushes B, so B pushes A back.
Either it accelerates, or its acceleration is zero.
| If the question says A… | Resultant force on A | So your link 5 says |
|---|---|---|
| changes speed (starts moving, speeds up, slows down) | Not zero, along the line of motion | A accelerates (or decelerates): its velocity and momentum change |
| changes direction (turns, spins, curves) | Not zero, at an angle to the motion | A accelerates even at a steady speed, because its velocity changes direction |
| moves at constant velocity (or stays still) | Zero: the forces are balanced | By Newton’s first law, A does not accelerate |
Solid carbon dioxideA changes state directly from solid to gas. This process is called sublimation. Solid carbon dioxide, when placed on water, will move rapidly across the surface due to jets of ejected gasB.
The diagram below shows the direction of movement for a large piece of solid carbon dioxide placed on water.
(a) When placed at rest on water, piece X begins to move rapidly in the direction shown.
With reference to Newton’s laws of motion explain the motion of piece X. (5)
1The solid carbon dioxide exerts a force on the gas, pushing the jet of gas out backwards.✓ 1 mark
2By Newton’s third law, the gas exerts a force on the solid carbon dioxide.✓ 1 mark
3This force is equal in size and opposite in direction to the force on the gas, so it pushes piece X in the direction shown.✓ 1 mark
4There is very little friction from the water, so this is a resultant (unbalanced) force on piece X.✓ 1 mark
5By Newton’s second law, a resultant force causes an acceleration, so piece X accelerates from rest: its velocity increases in the direction shown.✓ 1 mark
6Using F = ma: as the piece of ice has a small mass, there is a large acceleration for the same resultant force, so it moves rapidly.✓ 1 mark
Six marking points, five marks available: full marks with one to spare.
| Mark scheme says | Link | |
|---|---|---|
| Solid (CO2) exerts a force on the gas (CO2) | 1 A on B | (1) |
| N3 means (gas exerts) a force on the solid/X | 2 B on A | (1) |
| Force is in opposite direction on the solid/gas | 3 Equal & opp. | (1) |
| There is a resultant/unbalanced force (on the solid) | 4 Resultant | (1) |
| N2/1 means the (solid) accelerates (accept changes velocity/speed) | 5 Accelerates | (1) |
| Rapid because mass/friction is small | 6 So… | (1) |
| Max 5. No mark for a statement of Newton’s laws. Quality of written communication is assessed, so write it in order: the chain does that for you. | ||
Same chain, different objects. Mark up the question first (ring A, ring B, underline what A does), write your answer, then open the answer to see the mark-up, the chain and the mark scheme.
(b) As the train leaves the next station the passengerA holds on to a vertical supportB as the train accelerates. This prevents the passenger falling backwards.
With reference to Newton’s laws of motion, explain why holding on to a vertical support prevents the passenger falling backwards. (5)
1The passenger exerts a force on the support, pulling it backwards.✓ 1 mark
2By Newton’s third law, the support exerts a force on the passenger.✓ 1 mark
3This force is equal in size and opposite in direction, so it pulls the passenger forwards, the same way as the train accelerates.goes with 2
4This forward force is the resultant (unbalanced) force on the passenger.✓ 1 mark
5By Newton’s second law, a resultant force causes an acceleration, so the passenger accelerates forwards.✓ 1 mark
6The passenger accelerates at the same rate as the train, so they move with the train and do not fall backwards.✓ 1 mark
| Mark scheme says | Link | |
|---|---|---|
| Man pulls (backward) on the support | 1 A on B | (1) |
| Due to N3 the support exerts an (opposite) force on the man | 2–3 B on A | (1) |
| This force is a resultant/unbalanced/net force on man | 4 Resultant | (1) |
| Due to N1/N2 the man will accelerate | 5 Accelerates | (1) |
| With the same acceleration/speed/velocity as the train | 6 So… | (1) |
| 5 marks. Here “equal and opposite” shares a mark with the third law, so link 6 is the one you can’t skip: say same acceleration as the train. | ||
The diagram shows a toy carA driven by airB from a deflating balloon.
When the air in the inflated balloon is released, the car starts to move forwards.
(a) Use Newton’s first and third laws of motion to explain why the air coming out of the balloon causes this. (3)
1The balloon exerts a force on the air, pushing it out backwards.✓ mark 1
2By Newton’s third law, the air exerts a force on the balloon and car.✓ mark 1
3This force is equal in size and opposite in direction, so it pushes the car forwards.✓ mark 1
4The forward force is bigger than the friction and drag, so there is a resultant (unbalanced) force on the car.✓ mark 2
5By Newton’s first law, the car can only stay at rest if there is no resultant force, so the car accelerates.✓ mark 2
6So the car starts to move forwards, in the opposite direction to the air coming out.✓ mark 3
Only 3 marks, but the chain still works: links 1–3 earn mark 1, links 4–5 earn mark 2, and naming both laws in context earns mark 3.
| Mark scheme says | Link | |
|---|---|---|
| Uses N3: force (backward) on air by balloon/car, (so/=) force (forward) on balloon/car by air | 1–3 | (1) |
| Uses N1: resultant force / forces unbalanced / force on balloon > drag, (so) there is an acceleration / moves from rest / starts moving | 4–5 | (1) |
| Identifies the use of N1 or N3 (by name or description) correctly, linking it to the context | 2 and 5 | (1) |
Some questions have two groups. The people a seat pushes on get the chain: third law, then second law, so they slow down. The person nothing pushes on gets Newton’s first law: the resultant force is zero, so they keep going. The clue: a vehicle slows down suddenly and someone carries on moving.
The diagram shows three passengers sitting on a train that is travelling at a high speed in the direction shown. Seat belts are not used on trains.
With reference to one of Newton’s laws of motion, explain why seat C is the safest seat for a passenger to be sitting on in the event of a rapid deceleration. You may assume that the seats all remain fixed firmly to the floor and do not break. (4)
1When the train decelerates, passengers B and C push on the backs of their seats, to the right.goes with 2
2By Newton’s third law, seats B and C push the passengers to the left, with an equal and opposite force.✓ 1 mark
3This is a resultant force on B and C, so by Newton’s second law they decelerate (slow down) with the train and stay in their seats.✓ 1 mark
4No horizontal force acts on passenger A: their seat back is behind them, not in front.goes with 5
5The resultant force on A is zero, so by Newton’s first law A’s velocity does not change.✓ 1 mark
6So A continues to move forwards at the same speed while the train slows down.✓ 1 mark
7Passenger A hits passenger B.✓ 1 mark
8Nobody hits C, so seat C is the safest.answers the question
Five marking points, four marks available. Don’t write that A is “thrown forwards”: nothing throws them, they just keep going. The mark scheme refuses that mark.
| Mark scheme says | Link | |
|---|---|---|
| (B and) C will stay in their seats | 3 | (1) |
| Resultant force acts / chair exerts force on (B and) C, or (B and) C will decelerate | 1–3 | (1) |
| Passenger A continues to move (at the same speed). Not if A is “thrown/thrust/pushed” forward | 6 | (1) |
| Identifies movement of passenger A as Newton’s first law, in the context of the question | 4–5 | (1) |
| A will collide with B | 7 | (1) |
| Max 4. Just quoting N1 doesn’t score: it has to be about passenger A. | ||
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Spec-aligned revision resources, group courses, and 1:1 tutoring for GCSE and A Level Physics — built by an experienced teacher and examiner.