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Don't read anything yet. Each glowing ball is 1 coulomb of charge. On tab 1, press Count for 1 second and count the balls crossing the gold line, then compare your count with the ammeter. On tab 2, follow one ball round and watch what happens to its red joules in the battery and in the bulb, then add a second bulb. On tab 3, change the battery, then change the resistor, and see which one changes the resistance.
What the ammeter is telling you
Try this: press Count for 1 second and count the balls crossing the gold line yourself. Then turn the variable resistor up and count again.
Follow one charge round
1 volt = 1 joule per coulomb. The voltmeter does not count charges. It measures how much energy each coulomb hands over between its two wires.
Read the meters, then work out R
| V (volts) | I (amps) | R = V ÷ I (ohms) |
|---|---|---|
| Record a few readings: change the battery, then change the resistor. | ||
Charges are shown flowing in the direction of conventional current, from + to −. Cells are 1.5 V.
The exam wants the symbols drawn correctly, the meters in the right place, and the two equations Q = I t and V = I R used with the right units. The notes below cover all three.
You need to recognise and draw every one of these. Draw wires with a ruler, as straight lines that meet at right angles, and never leave a gap in a circuit unless it is an open switch.
Cell vs battery: a battery is two or more cells joined together. The long line is the positive (+) terminal.
Thermistor vs variable resistor: the thermistor's line has a flat foot at the bottom; the variable resistor's line ends in an arrowhead.
Resistor vs fuse: a fuse has a line running all the way through the box.
| Meter | Measures | How it is connected |
|---|---|---|
| Ammeter | current, in amps (A) | in series — in the same loop, so the charge flows through it |
| Voltmeter | potential difference, in volts (V) | in parallel — across the component, one wire on each side of it |
For a current to flow you need two things: a closed circuit (no gaps) and a source of potential difference, such as a cell or battery.
Electric current is the rate of flow of electrical charge.
In other words, current tells us how much charge passes a point every second. A current of 1 amp means 1 coulomb of charge passes each second; 3 A means 3 coulombs every second.
charge flow = current × time
Q charge, coulombs (C) · I current, amps (A) · t time, seconds (s)In a single closed loop the current is the same at every point. Charge is not used up by the bulb; it all comes back round to the battery.
Q = I t only works in amps and seconds. Convert before you substitute: mA ÷ 1000 → A (45 mA = 0.045 A) and minutes × 60 → s (2 min = 120 s).
Potential difference, also called voltage, tells us how much energy is transferred to or from each coulomb of charge. The battery gives energy to the charge; the bulb or resistor takes it and transfers it away, as light and heat.
The current through a component depends on both the potential difference across it and its resistance. More voltage pushes more current; more resistance lets less current through.
potential difference = current × resistance
V potential difference, volts (V) · I current, amps (A) · R resistance, ohms (Ω)I = V ÷ R to find the current.
R = V ÷ I to find the resistance: voltmeter reading ÷
ammeter reading.
For a fixed resistor, doubling the voltage doubles the current, so V ÷ I stays the same. Changing the battery does not change the resistor. Tab 3 of the animation lets you prove it.
Watch for kΩ: 1 kΩ = 1000 Ω. Convert before you calculate.
Every calculation on this page is worth marks for the same four steps. Write all four, even when you can do it in your head.
equation & answerconvertsubstitute
Worked example · charge · 3 marks
A phone charger supplies a current of 500 mA for 2 minutes. Calculate the charge that flows.
Where marks go missing: 500 × 2 = 1000 C. Neither number is in the right unit, so the answer is wrong by a long way.
Worked example · V = I R · 2 marks
A current of 0.4 A flows through a 15 Ω resistor. Calculate the potential difference across it.
Exam-style question · rearranging · 3 marks
The potential difference across a 2.2 kΩ resistor is 11 V. Calculate the current through it. Give your answer in milliamps.
Check your answer has all 4 parts: equation, conversion, substitution, and an answer with its unit. A number with no unit can lose the final mark.
Name all 15 circuit symbols, add the meters to two circuits, work out the charge through a torch, and find the total resistance of two resistors in series and in parallel, then check it with the meters.
AQA GCSE Physics Workbook · ELECTRICITY · pages 3, 4 & 6The full workbook covers the whole of Topic 4.2 Electricity, with exam-style questions and worked answers.
Everything above, explained out loud — useful for a last-minute recap, or if you'd rather hear it than read it.
Everything above, explained out loud — useful for a last-minute recap, or if you'd rather hear it than read it. The video is on its way.
Video coming soon
The walkthrough for this lesson is being filmed and will appear right here. Until then, the animation and the notes above cover every mark.
Pages 3, 4 and 6 of the workbook have the circuit symbols to name, the meters to add, the torch charge question and the series-and-parallel resistance question, each with full answers at the back.
Spec-aligned revision resources, group courses, and 1:1 tutoring for GCSE and A Level Physics — built by an experienced teacher and examiner.