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Also on the AQA spec (7408, 3.3.1.3) and the OCR A spec (H556, 4.4.4).
Don't read anything yet. Watch the blue wave travel to the fixed end and come back as the orange wave. The bold navy line is their sum: the only thing you would actually see. Then tap the string at a node and at an antinode: are the two waves in phase or in anti-phase there? Tabs 2 and 3 do the same with sound in an open tube and a closed tube: what is at each end? On tab 4, melt some chocolate and measure the speed of light.
↔ Swipe the picture sideways to see all of it
Sound is longitudinal: the air particles (the strip under the graph) move back and forth along the tube. The graph plots their displacement, the way exam questions draw it. A closed end is always a node (the air there can't move); an open end is always an antinode.
Superposition: at every point, the resultant displacement is the sum of the two waves' displacements. Watch the probe: the navy dot is always the blue arrow plus the orange arrow. Displacements are in units of one wave's amplitude, so the most the sum can be is 2.
↔ Swipe the picture sideways to see the whole bar
Why it works: microwaves reflect off the metal walls, so two waves travel in opposite directions and a standing wave forms. The chocolate melts fastest at the antinodes (the hot spots), and adjacent antinodes are λ/2 apart. The frequency is printed on the oven's label.
Two waves with a constant phase difference (so they must have the same frequency).
When two waves meet, the resultant displacement is the sum of the individual displacements. Superposition and interference: use them as the same word.
Progressive waves transfer energy.
A standing wave has no net transfer of energy, and its nodes and antinodes stay at fixed points.
Distances: adjacent nodes are λ/2 apart. Adjacent antinodes (two hot spots, two loudest points) are λ/2 apart. A node to the next antinode is λ/4.
The notes give you the three conditions, what happens at a node and an antinode, the λ/2 rule, and the microwave oven method, written the way the mark scheme wants it.
A standing wave (also called a stationary wave: Edexcel uses both names, AQA and OCR say “stationary”) is a wave with no net transfer of energy and a pattern of nodes and antinodes at fixed positions.
Two waves of the same type meet (coincide) and superpose.
They travel in opposite directions, because one is the reflection of the other.
A wave and its own reflection have the same frequency and wavelength, and a similar amplitude.
Coherent: two waves with a constant phase difference (so they have the same frequency).
Superposition: when two waves meet, the resultant displacement is the sum of the individual displacements.
In these answers, superposition and interference mean the same thing.
When a wave on a string hits a fixed end (like the bridge of a guitar), it reflects upside down: a 180° phase change (π rad, half a cycle). At the fixed end the two waves are always equal and opposite, so they cancel, and there is always a node there. The string is fixed, so it couldn't move anyway.
| Antinode | Node | |
|---|---|---|
| The two waves are | in phase (phase difference 0) | in anti-phase (phase difference 180°) |
| Interference | constructive | destructive |
| Path difference* | a whole number of wavelengths, nλ | an odd number of half wavelengths, (n + ½)λ |
| Displacement | oscillates between maximum + and − amplitude | zero all the time: no movement |
| Energy | most: brightest, loudest, highest, hottest | least: darkest, quietest, lowest, coldest |
* For two waves that set off in phase. On a string, count the half-wavelength flip at the fixed end as part of the path difference.
Adjacent nodes are λ/2 apart. Adjacent antinodes (two hot spots, two loudest points) are λ/2 apart. A node to the next antinode is λ/4.
So one “loop” of a standing wave is half a wavelength, and two loops make one wavelength.
Every point between two adjacent nodes moves in phase: they all reach their highest point together, just with different amplitudes. Points on either side of a node are in anti-phase (180°). This is different from a progressive wave, where the phase changes all the way along.
| Progressive wave | Standing wave | |
|---|---|---|
| Energy | transfers energy | no net transfer of energy |
| Pattern | moves along | nodes and antinodes at fixed points |
| Amplitude | the same at every point | varies: zero at nodes, maximum at antinodes |
| Phase | changes continuously along one wavelength | in phase between adjacent nodes; anti-phase across a node |
| Wavelength | distance between adjacent points in phase | twice the distance between adjacent nodes |
It is the same physics every time. Only the ends change: a fixed end of a string and a closed end of a tube are always nodes; an open end of a tube is always an antinode. In a tube the wave is sound, which is longitudinal, so the graph shows the displacement of the air particles along the tube.
| The ends | 1st harmonic | Harmonics you get | |
|---|---|---|---|
| String | node at each end | L = λ/2, so λ = 2L | all: f, 2f, 3f, 4f… |
| Open tube | antinode at each end | L = λ/2, so λ = 2L | all: f, 2f, 3f, 4f… |
| Closed tube | node at the closed end, antinode at the open end | L = λ/4, so λ = 4L | odd only: f, 3f, 5f… |
It must have a node at one end and an antinode at the other, so it can only fit an odd number of quarter wavelengths: λ/4, 3λ/4, 5λ/4… That gives f, 3f, 5f. The next one up from the 1st harmonic is the 3rd, not the 2nd.
Take out the turntable and heat a bar of chocolate (or cheese) until it melts in spots.
With the turntable in, the bar moves through the hot spots and melts evenly.The melted spots are antinodes. Adjacent spots are λ/2 apart, so double the spacing to get λ.
Measure across several spots and divide, to cut the uncertainty.Read the frequency off the oven's label (usually 2.45 GHz) and use c = f λ.
6.1 cm spacing → λ = 0.122 m → c = 2.99 × 10⁸ m s⁻¹.A diffraction grating (and Young's double slit) also gives bright and dark points by interference, but the waves spread out from the slits in the same direction, towards the screen. Nothing is reflected back on itself, so there are no nodes and antinodes on a string or in a box: it is not a standing wave.
the two waves what they do nodes and antinodes
Q1 · A string is fixed at one end and made to vibrate at the other. Explain how a standing wave forms on the string. [4]
Q2 · Explain why a point at a node does not move. [2]
Q3 · A student takes the turntable out of a microwave oven and heats a slab of chocolate. Adjacent melted spots are 6.1 cm apart. The oven's frequency is 2.45 GHz. Calculate the speed of the microwaves. [3]
Where marks go missing: using 6.1 cm as the wavelength. That gives 1.49 × 10⁸ m s⁻¹, exactly half the right answer. Also: forgetting GHz means × 10⁹, and cm to m.
Q4 · State two differences between a progressive wave and a standing wave. [2]
Q5 · Two points on a standing wave are on either side of a node. State the phase difference between them. [1]
180° (π rad): they are in anti-phase.
Q6 · A tube closed at one end is 0.33 m long. It resonates at its 1st harmonic. The speed of sound is 340 m s⁻¹. Calculate the frequency. [3]
Where marks go missing: using λ = 2L as if the tube were open, which gives 515 Hz, about double the right answer.
For “how does it form”, have all four: reflection, two coherent waves in opposite directions, superpose, then in phase → antinode and anti-phase → node. For any distance question, ask: adjacent nodes or antinodes? Then it is λ/2.
Fill in the standing-waves gap fill (nodes, antinodes, phase, path difference), then try the exam questions, with answers.
Edexcel A Level Physics · Topic 5 Waves · standing wavesThe free practice sheet for this lesson is on its way. Until then, the five exam questions above have full answers.
Everything above, explained out loud — useful for a last-minute recap, or if you'd rather hear it than read it.
Everything above, explained out loud — useful for a last-minute recap, or if you'd rather hear it than read it. The video is on its way.
Video coming soon
The walkthrough for this lesson is being filmed and will appear right here. Until then, the animation and the notes above cover every mark.
Practise nodes, antinodes, phase and the microwave oven method, with answers.
Spec-aligned revision resources, group courses, and 1:1 tutoring for GCSE and A Level Physics — built by an experienced teacher and examiner.