4.1.2.2 Efficiency — AQA GCSE Physics — Physics with Kate
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4.1.2.2
AQA GCSE Physics · Topic 4.1 Energy · Conservation and dissipation of energy

Efficiency

In this lesson you'll learn to: say what useful and wasted energy transfers are, use the efficiency equation in joules or in watts, rearrange it both ways, give your answer as a decimal or a percentage, and describe how to make a device more efficient.
Prefer to watch? Scroll to the bottom for the video on this topic A video walkthrough is coming soon — it will appear at the bottom of this page

Start here — have a play

Don't read anything yet. Drag the two sliders and watch the equation fill itself in. Then try to push the useful output above the total input — the widget will not let you, and the reason why is the most important idea on this page.

📌 AQA: only the formula is required. You will never be asked to draw or read a Sankey diagram for AQA GCSE Physics — they are not on your specification, so there are none in here. Everything on this topic comes from one equation, and this widget is that equation from three directions.

Set the energy going in, and how much of it does the job you wanted

Total input energy transfer 1000 J
Useful output energy transfer 250 J
useful output wasted (transferred to the thermal store of the surroundings)
The calculation
25%efficient

Notice what you cannot do. Push the useful output above the total input and the widget stops you. Efficiency can never be more than 1 (100%), because you cannot get more energy out than you put in — energy is never created.

Pick a device

right 0 streak 0

Both AQA equations, same idea. efficiency = useful output energy transfer ÷ total input energy transfer, and efficiency = useful power output ÷ total power input. Joules with joules, watts with watts — never mix them.

Physics With Kate · physicswithkate.com — AQA GCSE Physics 4.1.2.2

▲ One equation, three ways round. That is the whole of 4.1.2.2.

One equation. That really is all this topic is.

The notes below give you the equation in both of its AQA forms, how to rearrange it, when to answer as a decimal and when as a percentage, and the four ways of making a device more efficient that examiners ask for by name.

Read the notes ↓

Revision notes

Useful and wasted

Every device is given energy to do a job. Some of that energy does the job — that is the useful output. The rest is wasted, and it almost always ends up transferred to the thermal store of the surroundings, which spreads out and cannot be got back.

Efficiency is simply the fraction of the energy that did the job you wanted.

⚠ "Useful" depends on what you wanted

The same energy transfer can be useful in one device and wasted in another. A filament bulb heating the room is wasted energy, because you wanted light. An electric heater heating the room is useful, because heating is the job.

So never learn a list of "useful" and "wasted" transfers. Ask what the device is for.

The equation

⭐ The one you must know

efficiency = useful output energy transfer ÷ total input energy transfer

AQA also gives it in terms of power, and it works exactly the same way:

efficiency = useful power output ÷ total power input

Use joules with joules, or watts with watts. Never mix the two.

Because you are dividing joules by joules (or watts by watts), the units cancel — so efficiency is never measured in joules, watts, or anything else. What you write after the number depends on which form you give the answer in, and there are only two:

⭐ What to write after the number

As a decimal — nothing at all. Write 0.08 on its own. No J, no W, and no % sign, because 0.08 is not eight per cent.

As a percentage — the % sign is required. Write 8%. Leaving the % off turns your answer into 8, which is a hundred times too big and cannot be right, since efficiency can never be above 1.

So "efficiency has no unit" means no J and no W — it does not mean you can drop the per cent sign.

Decimal or percentage?

The equation always gives a decimal between 0 and 1. To turn it into a percentage, multiply by 100.

CalculationAs a decimalAs a percentage
250 J useful out of 1000 J in0.2525%
45 J useful out of 60 J in0.7575%
18 W useful out of 20 W in0.990%

Read the question. If it says "give your answer as a percentage", the decimal on its own is not the answer. If it does not say, either is accepted — but say which you have given.

Rearranging it

Two of the three quantities are always given, so you need the equation all three ways round:

  • efficiency = useful ÷ total
  • useful output = efficiency × total input
  • total input = useful output ÷ efficiency

If you are working from a percentage, turn it into a decimal first — 80% becomes 0.8. Multiplying by 80 instead of 0.8 is the single most common slip on this topic.

⭐ A check that costs you two seconds

Your efficiency must come out between 0 and 1 (or 0% and 100%). If it does not, you have divided the wrong way round — the useful output goes on top.

Why nothing is ever 100% efficient

Energy is never created or destroyed, so you can never get more out than you put in. But you always get less useful energy out, because some is dissipated — spread out into the surroundings where it cannot be used.

The usual culprits are:

  • friction between moving parts, which heats them up;
  • air resistance on anything moving through air;
  • sound from a device that vibrates;
  • resistance in electrical wires, which heats them.

The one near-exception is an electric heater, which is about 100% efficient — not because it is cleverly built, but because the thermal store is the useful output, so almost nothing counts as waste.

Making a device more efficient

The trick is always the same: reduce the wasted transfer. Learn one method for each cause, and say what it reduces — the mark is in the reason, not the word.

MethodWhat it reducesExample
Lubrication — oil or grease the moving partsfriction between surfaces, so less energy is dissipated as heatingoiling a bicycle chain or a motor's bearings
Insulation — lag or double-glazethe rate of energy transfer by heating out of the systemloft insulation, a lagging jacket on a hot water tank
Streamlining — smooth the shapeair resistance, so less energy is wasted pushing air asidethe shape of a car or a train
Better componentsthe waste built into the device itselfan LED bulb instead of a filament bulb

What you do NOT needSankey diagrams are not required for AQA GCSE Physics. You will not be asked to draw one, label one, or read values off one, and there are none anywhere on this page.

If you have seen them in a textbook, on a poster, or from a friend on a different course, you are not missing a topic — they belong to other specifications, such as Edexcel International GCSE. For AQA, everything on efficiency comes from the one equation above.

Worked examples

A lamp is supplied with 500 J of energy and usefully transfers 40 J as light. Calculate its efficiency.

efficiency = useful ÷ total = 40 ÷ 500 = 0.08 — a decimal, so nothing is written after it.
As a percentage that is 0.08 × 100 = 8% — and here the % sign is needed. Either form is accepted, but "0.08%" and a bare "8" are both wrong.

A motor is 75% efficient. It is supplied with 1200 J. How much energy is usefully transferred?

Turn the percentage into a decimal first: 75% = 0.75.
useful = efficiency × total = 0.75 × 1200 = 900 J
So 300 J is wasted, mostly heating the motor through friction.

A kettle usefully transfers 180 kJ to the water and is 90% efficient. How much energy was supplied to it?

total = useful ÷ efficiency = 180 ÷ 0.9 = 200 kJ
Check it looks right: the total must be bigger than the useful output. 200 kJ > 180 kJ ✓

A device has a total power input of 60 W and a useful power output of 21 W. Calculate the efficiency as a percentage.

efficiency = 21 ÷ 60 = 0.35, so 35%.
Watts divided by watts — the power equation works exactly like the energy one. The question asked for a percentage, so the % sign must be there; no W and no J ever appear after an efficiency.

A student calculates an efficiency of 2.5. Explain why this must be wrong.

Efficiency can never be greater than 1, because that would mean more energy coming out than went in, and energy cannot be created. The student has divided total by useful instead of useful by total.

📘 Now do it in your workbook

Work through the efficiency calculations yourself — forwards, then both rearrangements — and check them against the answers at the back of the book.

AQA GCSE Physics Workbook · ENERGY · page 14

Free sample = the pages for this lesson. The full workbook covers the whole Energy topic for AQA, with exam-style questions and worked answers.

✅ Can you do it? Tick as you go

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🎉 Nice work! You've ticked off every objective for this spec point. Don't forget to hit “Mark complete” at the bottom of the lesson.

Prefer to watch? Here's the whole thing

Video walkthrough — coming soon

Everything above, explained out loud — useful for a last-minute recap, or if you'd rather hear it than read it.

Everything above, explained out loud — useful for a last-minute recap, or if you'd rather hear it than read it. The video is on its way.

🎬

Video coming soon

The walkthrough for this lesson is being filmed and will appear right here. Until then, the notes and the free workbook pages above cover every mark.

▲ In GHL you can also use the lesson's built-in video field instead of this embed.

Now put it into practice

Watching someone else rearrange an equation is not the same as rearranging it yourself. The workbook pages give you the calculations all three ways round, with worked answers at the back.

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